Skip to main content
12 events
when toggle format what by license comment
Oct 19, 2023 at 15:52 vote accept Andromeda
S Oct 3, 2023 at 15:12 history bounty ended Andromeda
S Oct 3, 2023 at 15:12 history notice removed Andromeda
Oct 2, 2023 at 15:42 answer added Matthew Daws timeline score: 4
Oct 2, 2023 at 5:19 comment added Andromeda @YemonChoi Thanks for your suggestion. I also thought about this: roughly, the idea would be to extend the map $\Delta: A \to M(A\otimes A)$ to a comultiplication $A^{**}\to A^{**}\bar{\otimes}A^{**}$. This dualises then to a multiplication map on $(A^{**})_* = A^{*}$. However, in general, it is not clear to me that we can find this extension to the bidual. In many cases of interest, this seems true: namely, it is true for those Hopf $C^*$-algebras that arise from a locally compact quantum group. Indeed, in that case the comultiplication is implemented by a multiplicative unitary.
Oct 2, 2023 at 2:26 history edited Yemon Choi
Adding the OA tag to bring this to the attention of specialists who may know how to deal with this question
Oct 2, 2023 at 2:25 comment added Yemon Choi I don't have a complete answer, but the way this works for Hopf von Neumann algebras is that the vN spatial tensor product of M with itself can be identified with the dual of $M_* \hat\otimes M_*$ where $\hat\otimes$ is the projective tensor product of operator spaces. I suspect that one could try to adapt, or build on, this result by passing from A to its bidual, but I have not tried to check the details yet.
S Sep 26, 2023 at 11:29 history bounty started Andromeda
S Sep 26, 2023 at 11:29 history notice added Andromeda Draw attention
Sep 25, 2023 at 12:12 history edited Andromeda CC BY-SA 4.0
added 36 characters in body
Sep 22, 2023 at 22:24 history edited Andromeda CC BY-SA 4.0
added 11 characters in body
Sep 22, 2023 at 8:33 history asked Andromeda CC BY-SA 4.0