Timeline for Tests for determining membership of exponential family
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Sep 20, 2023 at 20:22 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Sep 20, 2023 at 20:13 | comment | added | Iosif Pinelis | @AaronHendrickson : Right. I specified $x_0$ to be $0$, but I did not have to (I was just pretty sure that any $x_0$ would work). | |
| Sep 20, 2023 at 20:08 | comment | added | Aaron Hendrickson | Also worth noting that your derivation holds if you define $G$ as $G_{\theta_0,x_0}(\theta,x):=g(\theta,x)+g(\theta_0,x_0)-g(\theta,x_0)-g(\theta_0,x)$ | |
| Sep 20, 2023 at 20:04 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Sep 20, 2023 at 19:58 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Sep 20, 2023 at 19:35 | comment | added | Iosif Pinelis | I have not seen this reasoning elsewhere, but it should be used somewhere, as your question is quite natural and should be rather common. | |
| Sep 20, 2023 at 17:22 | vote | accept | Aaron Hendrickson | ||
| Sep 20, 2023 at 16:37 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |