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S Sep 25, 2023 at 14:05 history bounty ended CommunityBot
S Sep 25, 2023 at 14:05 history notice removed CommunityBot
Sep 18, 2023 at 11:57 history edited tony CC BY-SA 4.0
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Sep 17, 2023 at 13:46 history edited tony CC BY-SA 4.0
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Sep 17, 2023 at 13:36 history edited tony CC BY-SA 4.0
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Sep 17, 2023 at 13:31 comment added tony @CommandMaster $L$ is increasing function of $n$ but it is fine if considering it as constant can make problem simpler. And $N(n)\in\{0,1,2,\cdots,\lfloor \frac{n^2-2\sqrt{2} n^{3/2}-2cn^{1+\epsilon}}{2} \rfloor\}$.
Sep 17, 2023 at 13:28 history edited tony CC BY-SA 4.0
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Sep 17, 2023 at 13:25 comment added tony @CommandMaster There are two steps, first to partition the set $\{1,\cdots,n\}$, thus there are $\frac{n!}{\Pi_i (p_i!)^{a_i} \Pi_i a_i!}$ ways to do that; Second, for example $n=3$ and partition $\{1,2\}\{3\}$, denoted as $\{x_1,x_2\}\{x_3\}$, we want to assign values from $\{1,\cdots,L\}$ to them such that $x_1=x_2$ and $x_1\neq x_3$, $x_2\neq x_3$. Thus there are $\binom{L}{2}2!$ ways of assignments.
Sep 17, 2023 at 13:21 history edited tony CC BY-SA 4.0
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Sep 17, 2023 at 13:13 history edited tony CC BY-SA 4.0
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Sep 17, 2023 at 12:56 comment added Daniel Weber Is $L$ a constant as $n\to\infty$? What about $N$?
Sep 17, 2023 at 12:54 comment added Daniel Weber Just to make sure I understand the question: you want to estimate the number of partitions of $\{1,2,...,n\}$ such that there are $N$ pairs with both elements in the same part, and each partition is weighted $\frac{L!}{(L-m)!}$ where $m$ is the number of parts?
S Sep 17, 2023 at 12:16 history bounty started tony
S Sep 17, 2023 at 12:16 history notice added tony Draw attention
Sep 17, 2023 at 12:11 history edited tony CC BY-SA 4.0
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Sep 15, 2023 at 15:39 history edited tony CC BY-SA 4.0
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Sep 15, 2023 at 11:37 history edited tony CC BY-SA 4.0
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Sep 15, 2023 at 9:31 history edited tony CC BY-SA 4.0
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Sep 15, 2023 at 8:38 history edited tony CC BY-SA 4.0
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Sep 15, 2023 at 8:18 history edited tony CC BY-SA 4.0
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Sep 15, 2023 at 8:07 comment added tony @DaveBenson Indeed, thank you! Now I added the motivation part.
Sep 15, 2023 at 8:06 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 19:05 comment added Dave Benson The downvote not being mine, I'm just guessing, but it seems to me that the problem with this post is the equation barf without motivational text. Why are you interested, where did this come from, and what would it do for you?
Sep 14, 2023 at 17:13 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 15:05 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 15:00 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 14:51 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 13:42 comment added tony @SeanSanford Thanks. but the expression in my post is exact, and I have no idea how to make the post less broad..
Sep 14, 2023 at 13:12 comment added Sean Sanford perhaps they thought your question was too broad in scope. fwiw this looks like you might want to search the term 'multinomial'
Sep 14, 2023 at 13:02 comment added tony could the down-voted be explained so that I can improve my question?
Sep 14, 2023 at 12:18 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 10:54 history edited tony CC BY-SA 4.0
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Sep 14, 2023 at 10:40 history asked tony CC BY-SA 4.0