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Timeline for Connected geometric thickness two

Current License: CC BY-SA 4.0

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S Oct 23, 2023 at 16:06 history bounty ended CommunityBot
S Oct 23, 2023 at 16:06 history notice removed CommunityBot
Oct 22, 2023 at 1:43 comment added Jan Nienhaus If you are happy with an infinite example, I think $\mathbb{Z}^2$ with edges of slopes $(1,0),(0,1),(1,2),(1,3),(2,1),(3,1)$ does the trick.
Oct 20, 2023 at 1:11 comment added Alex Ravsky @domotorp The closest result which I know is Fig. 3 from the paper Thickness and colorability of geometric graphs (Computational Geometry 56 (2016) 1-18) by Stephane Durocher, Ellen Gethner, Debajyoti Mondal, where are shown "all the three combinatorially different configurations of nine points that support geometric thickness-two drawings of" $K_9$ without an edge.
Oct 20, 2023 at 0:20 comment added Jan Nienhaus This condition can be seen to be equivalent to requiring that all components of $G_1, G_2$ have at least one edge (i.e. have no isolated points) for all valid decompositions, but I also can't find an example where this seemingly weaker condition seems to hold.
Oct 19, 2023 at 4:18 comment added domotorp Do you know of any graph that has a unique geometric thickness two embedding? I feel like that could be a good start for a construction.
S Oct 15, 2023 at 14:52 history bounty started Lorenzo Pompili
S Oct 15, 2023 at 14:52 history notice added Lorenzo Pompili Draw attention
S Oct 15, 2023 at 13:46 history bounty ended Alex Ravsky
S Oct 15, 2023 at 13:46 history notice removed Alex Ravsky
Oct 9, 2023 at 2:32 comment added Alex Ravsky @quarague Sulanke's nine-color Earth–Moon map has $11$ vertices and $50$ edges, whereas any $11$-vertex graph of geometric thickness two has at most $48$ vertices, see the paper ``On representations of some thickness-two graphs'' (Computational Geometry 13 (1999) 161–171) by Joan P. Hutchinson, Thomas Shermer, and Andrew Vince.
Oct 7, 2023 at 13:22 comment added Alex Ravsky Unfortunately, it seems that I found the disconnected drawings for all graphs form my answer. So I deleted it and returned the bounty.
S Oct 7, 2023 at 13:20 history bounty started Alex Ravsky
S Oct 7, 2023 at 13:20 history notice added Alex Ravsky Draw attention
S Oct 7, 2023 at 12:20 history bounty ended Till
S Oct 7, 2023 at 12:20 history notice removed Till
Oct 7, 2023 at 9:48 answer added Alex Ravsky timeline score: 3
S Oct 1, 2023 at 15:21 history suggested Lorenzo Pompili CC BY-SA 4.0
I removed parentheses and highlighted more the fact that edges are straight lines, as the term “plane” can also refer to graphs with curved edges.
Oct 1, 2023 at 14:12 review Suggested edits
S Oct 1, 2023 at 15:21
Sep 30, 2023 at 13:52 answer added Lorenzo Pompili timeline score: 6
Sep 30, 2023 at 12:16 history edited Wlod AA CC BY-SA 4.0
connected
S Sep 30, 2023 at 10:23 history bounty started Till
S Sep 30, 2023 at 10:23 history notice added Till Draw attention
Sep 14, 2023 at 14:27 history edited Till CC BY-SA 4.0
added 66 characters in body
Sep 14, 2023 at 14:26 comment added Till @quarague: the wikipedia page considers thickness and not geometric thickness of a graph. I do not think that the graph on the Wikipedia page has geometric thickness 2. I did not check the graph carefully though. Thanks for the pointer.
Sep 14, 2023 at 14:22 comment added Till - Yes, the term plane, means representing edges by segments. Good question. - Clearly, you can find a decomposition of the edges that make the drawing connected. That is easy. The difficult part is to find a graph such that every embedding and decomposition has this property.
Sep 14, 2023 at 13:47 comment added quarague Did you check whether the Sulanke's nine-color Earth–Moon map on the wikipedia page for graph thickness en.wikipedia.org/wiki/Thickness_(graph_theory) is such an example?
Sep 14, 2023 at 13:34 comment added Peter Taylor @quarague, by exhaustion no subgraph of $K_6$ serves as an answer.
Sep 14, 2023 at 13:10 comment added quarague From some doodling, for $K_5$ there exists an embedding and a decomposition such that $G_1$ and $G_2$ are plane and connected. I don't think any decomposition is doable, for example it implies that for every vertex any decomposition needs to asign at least one adjacent edge to each part of the decomposition.
Sep 14, 2023 at 11:51 comment added Ilya Bogdanov Do you assume that all edges are represented by segments?
Sep 14, 2023 at 11:42 history edited YCor CC BY-SA 4.0
removed capitals from title, changed tag
Sep 14, 2023 at 10:04 history asked Till CC BY-SA 4.0