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Sep 13, 2023 at 23:31 comment added Matt Zaremsky I'd say another "candidate" comes from Thompson's group $F$. Let $\phi:F\to\mathbb{Z}$ send $f$ to the log base 2 of the slope of $f$ at 0 plus the log base 2 of the slope of $f$ at 1. Then the kernel of $\phi$ is finitely generated but not finitely presented. I wouldn't be surprised if all the non-trivial mapping tori of this kernel are isomorphic to $F$, or really close. And $F$ has lots of automorphisms, so if this turned out to work, it would be "interesting".
Sep 13, 2023 at 15:49 comment added YCor The non-fp group $\mathbf{Z}\ltimes (\mathbf{Z}[1/2]^2)$, action by diagonal $(2,2^{-1})$ might be more interesting to look at. Of course one can cheat and act by a virtually inner automorphism (e.g., flip of components). But otherwise any "non-inner enough" automorphism is likely to produce a fp group.
Sep 13, 2023 at 15:43 comment added YCor @Carl-FredrikNybergBrodda No, it doesn't have any.
Sep 13, 2023 at 14:50 comment added Moishe Kohan As a toy model one can ask the same question about nontrivial mapping tori which are all finitely generated. Does it imply finite generation of the original group?
Sep 13, 2023 at 13:23 comment added Benjamin Steinberg You might look at the comments to mathoverflow.net/questions/104400/…
Sep 13, 2023 at 11:01 comment added Carl-Fredrik Nyberg Brodda What happens for the lamplighter group? Does it have any finitely presented mapping torus?
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