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Sep 16, 2023 at 6:34 vote accept Dominic van der Zypen
Sep 15, 2023 at 18:41 answer added Elliot Glazer timeline score: 7
Sep 15, 2023 at 17:36 comment added Andreas Lietz Youre right, I was talking nonsense!
Sep 15, 2023 at 16:33 comment added Peter LeFanu Lumsdaine @AndreasLietz: I don’t follow either, but for a different reason than Elliot Glazer. In trying to proving $\mathbf{C}_2$ (or even full choice) over a well-ordered base by induction, the difficulty at limit steps isn’t in choosing the “next point”, it’s in picking earlier choices for all previous steps together.
Sep 15, 2023 at 16:29 comment added Elliot Glazer @AndreasLietz I don't follow. The two different possibilities will have the same parity.
Sep 14, 2023 at 11:16 comment added Dominic van der Zypen Thanks @JoelDavidHamkins for spotting my mistake, I intended to ask about the other implication and have corrected my error.
Sep 14, 2023 at 6:31 history edited Dominic van der Zypen CC BY-SA 4.0
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Sep 13, 2023 at 10:53 comment added Joel David Hamkins Have you asked the question you intended? It seems we know that it does by the linked question, as you say.
Sep 13, 2023 at 10:27 history asked Dominic van der Zypen CC BY-SA 4.0