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Added a remark (Dave Benson's answer for the case that G is finite).
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Stefan Kohl
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Let $G$ be a group which is generated by the set of its involutions, and assume that the product of every two involutions in $G$ has order a power of 2. Is it possible that $G$ has an element of odd order $\neq 1$?

Added on Sep 7, 2023: Dave Benson gave a nice answer for the case that $G$ is finite. However, the more interesting general case remains open so far.

Let $G$ be a group which is generated by the set of its involutions, and assume that the product of every two involutions in $G$ has order a power of 2. Is it possible that $G$ has an element of odd order $\neq 1$?

Let $G$ be a group which is generated by the set of its involutions, and assume that the product of every two involutions in $G$ has order a power of 2. Is it possible that $G$ has an element of odd order $\neq 1$?

Added on Sep 7, 2023: Dave Benson gave a nice answer for the case that $G$ is finite. However, the more interesting general case remains open so far.

Can a group generated by its involutions, the product of every two of which has order a power of 2, have an element of odd order?

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Stefan Kohl
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Can a group generated by its involutions the product of every two of which has order a power of 2 have an element of odd order?

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Stefan Kohl
  • 19.6k
  • 21
  • 75
  • 137
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