Skip to main content
3 events
when toggle format what by license comment
Sep 4, 2023 at 13:32 comment added Sam Hopkins So more generally if we have two formal power series $A(x)=\sum_{n \geq 1} a_n x^n$, $B(x) = \sum_{n \geq 1} b_n x^n$ that are compositional inverses $A^{\langle -1 \rangle} = B$, then we get the same formula $g_n = \sum_{(c_1,\ldots,c_k)\models n} a_k f_{c_1} \cdots f_{c_k} \Leftrightarrow f_n = \sum_{(c_1,\ldots,c_k)\models n} b_k g_{c_1} \cdots g_{c_k}$. The case from the question-asker is given by taking $A(x) = e^x - 1$ and $B(x) = \log(x+1)$.
Sep 2, 2023 at 2:11 history edited LSpice CC BY-SA 4.0
Title of this blog post
Sep 1, 2023 at 19:27 history answered Qiaochu Yuan CC BY-SA 4.0