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Sep 3, 2023 at 0:27 comment added Xin Jin @DavidRoberts Yes, a category enriched over Top.
Sep 2, 2023 at 23:54 comment added David Roberts What do you mean by topological category? Enriched over Top?
Sep 2, 2023 at 20:31 vote accept Xin Jin
Sep 2, 2023 at 19:48 answer added Dmitri Pavlov timeline score: 5
Sep 2, 2023 at 19:17 history edited Xin Jin CC BY-SA 4.0
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Sep 2, 2023 at 19:11 comment added Xin Jin For the latter, it seems there might be a way to make a "big" canonical topological category whose objects are all points $x\in X$ and between different points $x,x'$ the morphism space is the space of paths connecting $x, x'$. But the result is equivalent to $B(\Omega_xX)$. By the way, I'm more interested in whether the construction (1) realizes $N$.
Sep 2, 2023 at 19:09 comment added Xin Jin @DmitriPavlov: $Cat_\infty$ is the $\infty$-category of quasi-categories. It is either $(Set_\Delta)^{J,cf}$ as an $\infty$-category or modeled as the $\infty$-category of complete Segal spaces. I agree the construction of (2) depends on choices of basepoints, which is similar to $B(\Omega_x X)\simeq X$ for a connected space $X$. Actually, my intuition of (2) is from the "correspondence" from a connected space $X$ as a quasi-category, to the topological category $B(\Omega_x X)$ (with a single object and endomorphism space $\Omega_x X$).
Sep 2, 2023 at 13:59 comment added Dmitri Pavlov What is Cat_∞? It is not defined in your post. Also, you seem to claim that (1) and (2) define adjoint functors, but (2) starts with an ∞-category (which presumably means quasicategory here), and it seems that your Cat_∞ means something else than quasicategories. Finally, the construction of (2) as it is currently stated makes noncanonical choices of basepoints, so it is not even a functor, let alone an adjoint functor.
Sep 1, 2023 at 19:11 history asked Xin Jin CC BY-SA 4.0