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Sep 3, 2023 at 13:08 comment added total dependent random choice @SamHopkins I'm looking for some references that discuss explicitly discusses these kind of identities. Sorry for the confusion :)
Sep 2, 2023 at 17:31 comment added total dependent random choice @TomCopeland I would have to check with my Prof. to see if I can share those :)
Sep 2, 2023 at 15:26 comment added Tom Copeland Do you have a link to those or similar lecture notes of your professor?
Sep 2, 2023 at 15:01 answer added Tom Copeland timeline score: 3
Sep 2, 2023 at 6:46 comment added total dependent random choice @LSpice Lecture notes made by my professor
Sep 2, 2023 at 2:05 comment added LSpice Your image seems to be taken from somewhere. Where?
Sep 2, 2023 at 1:18 history became hot network question
Sep 1, 2023 at 19:27 answer added Qiaochu Yuan timeline score: 12
Sep 1, 2023 at 19:21 history edited YCor CC BY-SA 4.0
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Sep 1, 2023 at 18:08 comment added total dependent random choice @SamHopkins Well I'm working with someone(Mahajan) who's a very close collaborator with one of authors in the above mentioned paper, and this paper was one of the reason why I am looking for resources done by other authors on studying this problem. I guess there is not a lot of work being done here! Please let me know if there is some other work that also deals with this problem! Also, thank you for taking your time to research for me, really appreciate it!
Sep 1, 2023 at 17:50 comment added total dependent random choice @darijgrinberg I know I'm asking too much, but is there any reference, that deals precisely with the identity I have mentioned above?
Sep 1, 2023 at 17:41 comment added darij grinberg The general form here is "if a sequence $\left(g_0, g_1, g_2, \ldots\right)$ is obtained from a sequence $\left(f_0, f_1, f_2, \ldots\right)$ by some polynomial map $P = \left(P_0, P_1, P_2, \ldots\right)$, then $\left(f_0, f_1, f_2, \ldots\right)$ is in turn obtained from $\left(g_0, g_1, g_2, \ldots\right)$ by a certain polynomial map $Q = \left(Q_0, Q_1, Q_2, \ldots\right)$", right? Such identities are often called inversion formulas (e.g., binomial inversion) when the polynomials in question are linear. As you have noticed, compositionally inverse power series also yield such identities.
Sep 1, 2023 at 17:25 comment added total dependent random choice @SamHopkins Do you know any resource that deals with this particular form of identities?
Sep 1, 2023 at 17:21 history edited total dependent random choice CC BY-SA 4.0
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S Sep 1, 2023 at 17:18 review First questions
Sep 1, 2023 at 19:41
S Sep 1, 2023 at 17:18 history asked total dependent random choice CC BY-SA 4.0