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Sep 1, 2023 at 20:57 vote accept Armando j18eos
Sep 1, 2023 at 13:19 comment added Donu Arapura Restrict $\Omega_X^1$ to $C_1\times pt$, then one factor is a trivial line bundle, so it can't be ample.
Sep 1, 2023 at 12:50 comment added Armando j18eos Ok: $X$ is of general type with $K_X$ ample and $\Omega^1_X$ nef. However, why $\Omega^1_X$ is not ample?
Sep 1, 2023 at 11:56 history answered Donu Arapura CC BY-SA 4.0