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Aug 28, 2023 at 8:17 comment added grok It has order $2^{167}$, and can be produced in GAP with the commands LoadPackage("anupq"); and Pq(FreeGroup(2):Prime:=2,ClassBound:=8);
Aug 25, 2023 at 12:13 comment added YCor I indeed understood incorrectly as I often used $k$-nilpotent to mean $k$-step-nilpotent. OK, I understand now (that's "8-step-(2-nilpotent)" in some sense). This is a quite big group then, what's its order?
Aug 25, 2023 at 10:29 comment added grok No, you understood correctly: the $2$-nilpotent refers to the prime $2$, while $8$ is the class. Start with $G_1=F$ the free group on $2$ generators, and define $G_{i+1}=[G_i,F]\mho_1(G_i)$. I did the calculations in $F/G_8$.
Aug 24, 2023 at 13:32 comment added YCor However I did the calculation on the free 2-step-nilpotent exponent-8 group on 2 generators (which has order $2^8$) and it seems to me that both $\mho_1(\mho_2(G))$ and $\mho_2(\mho_1(G))$ are trivial therein. I might have misunderstood something.
Aug 24, 2023 at 8:48 comment added YCor Class 8: you mean exponent 8? Class usually refers to nilpotency class (which is 2 here).
Aug 24, 2023 at 8:45 history answered grok CC BY-SA 4.0