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Aug 25, 2023 at 19:46 comment added Iosif Pinelis @MichaelHardy : Hardly far simpler for $n\ge4$. See Plackett's paper linked in my answer.
Aug 25, 2023 at 19:29 comment added Michael Hardy @IosifPinelis : oh . . . . Somehow I missed the part about the boundaries going straight through the origin. I think that makes it far simpler.
Aug 24, 2023 at 18:27 history edited Ye He CC BY-SA 4.0
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Aug 24, 2023 at 18:13 history edited Ye He CC BY-SA 4.0
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Aug 24, 2023 at 18:02 comment added Iosif Pinelis @MichaelHardy : An expression in elementary functions exists for $n\le3$ -- see my answer (mathoverflow.net/a/453379/36721). The hyperplanes are through the origin; so, your $c$ must be $0$.
Aug 24, 2023 at 17:23 comment added Michael Hardy I doubt this has a closed form even in the case of the intersection of two half-planes when $n=2.$ If the two half-planes are orthogonal to each other, then it's reducible to two instances of the one-dimensional case. But even the one-dimensional case my require numerical methods: What is $\operatorname E(Z^2\mid Z>c)$ when $Z\sim\operatorname N(0,1)\text{?} \qquad$
Aug 24, 2023 at 17:15 history edited Michael Hardy CC BY-SA 4.0
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Aug 24, 2023 at 14:57 history edited Ye He CC BY-SA 4.0
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Aug 24, 2023 at 14:57 comment added Ye He Thanks for the comment. Yes, I mean intersection of half spaces.
Aug 24, 2023 at 14:26 answer added Iosif Pinelis timeline score: 4
Aug 24, 2023 at 7:22 comment added Max Horn You write "hyperplanes" but then describe half spaces. Since you talk about defining a polytope as their intersection, I assume you meant "half spaces"? Please clarify your question either way :-)
Aug 24, 2023 at 6:46 history edited YCor CC BY-SA 4.0
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