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Tony
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Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in H$$g \in G$ satisfies $g h g^{-1} \in G$$g h g^{-1} \in H$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in H$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in G$ satisfies $g h g^{-1} \in H$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

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Tony
  • 21
  • 2

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in G$$g \in H$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in G$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in H$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

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Tony
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Normalizers in linear algebraic groups

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in G$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

Normalizers in algebraic groups

Let $G$ be a connected algebraic group and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in G$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

Normalizers in linear algebraic groups

Let $G$ be a connected linear algebraic group (say, over an algebraically closed field) and let $H < G$ be a closed connected subgroup. Let $N_G(H)$ be the normalizer of $H$ in $G$, and assume that $N_G(H)=H$. Does there necessarily exist a single element $h \in H$ such that if $g \in G$ satisfies $g h g^{-1} \in G$, then $g \in H$?

In the setting I am in $H$ is solvable, but I doubt that is relevant to the question.

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Tony
  • 21
  • 2
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