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Aug 21, 2023 at 20:38 answer added Harry Richman timeline score: 2
Aug 20, 2023 at 21:13 comment added Jean Marie Becker Have a look at this answer here on stack exchange making the connection with its inverse which is a version of the second differentiation operator, either in its discrete or in the continuous case.
Aug 19, 2023 at 5:18 history became hot network question
Aug 19, 2023 at 1:22 answer added Friedrich Knop timeline score: 7
Aug 19, 2023 at 0:51 comment added user44191 If there is, then it likely will be found close to a name for the family of upper-triangular matrices where all entries above or on the diagonal are $1$. These matrices can be seen as $A^T A$, where $A$ is such an upper-triangular matrix.
S Aug 18, 2023 at 21:14 review First questions
Aug 19, 2023 at 0:51
S Aug 18, 2023 at 21:14 history asked bldavies CC BY-SA 4.0