Timeline for Why do infinite-dimensional vector spaces usually have additional structure?
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
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| Aug 18, 2023 at 8:39 | comment | added | Jochen Wengenroth | But the vector space structur is needed to define the linear partial differential operator. | |
| Aug 16, 2023 at 22:42 | comment | added | Jochen Glueck | Hmm, I'm not sure I find this perspective convincing (with regard to the question at hand). I mean, you're technically right of course. But with the same reasoning one can also say that Malgrange's theorem has nothing to do with $C^\infty(\Omega)$ being a vector space. | |
| Aug 16, 2023 at 21:19 | history | answered | Jochen Wengenroth | CC BY-SA 4.0 |