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Oct 22, 2023 at 14:47 comment added Oscar Lanzi In all other Platonic solids, faces are three- or fourfold rotations of each other, which allows sets of corresponding points to fit into the integer lattice (by properly positioning and scaling the polyhedron). But with the icosahedron the rotation is fivefold, which precludes fitting one set of corresponding points to the integer lattice on all faces.
Aug 20, 2023 at 3:12 comment added Steven Stadnicki Curious side question: is it possible that the answer depends on the dimension? (e.g., that such an icosahedron exists in $\mathbb{R}^4$ but not $\mathbb{R}^3$)
Aug 20, 2023 at 2:58 history edited bof CC BY-SA 4.0
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Aug 20, 2023 at 0:13 history edited Ilya Bogdanov CC BY-SA 4.0
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Aug 17, 2023 at 16:10 comment added Jeremy Rouse Here's an example that doesn't work but comes close. The icosahedron with vertices $(\pm (\phi-2), \pm (\phi-1), 0)$, $(\pm (\phi - 1), 0, \pm (\phi - 2))$, $(0, \pm (\phi-2), \pm (\phi-1))$ has the property that each point in the set $\{ (1,1,-1), (1,-1,1), (1,-1,-1), (-1,1,1), (-1,1,-1), (-1,-1,1) \}$ lies on six of the extended faces of the icosahedron (with each extended face having at least one). However, one can show that for 12 of the faces of this icosahedron, any rational point lies a distance at least $\sqrt{2}$ from the origin, while the circumradius is $\sqrt{7-4\phi} < \sqrt{2}$.
Aug 17, 2023 at 10:23 comment added Yaakov Baruch I'm curious: is there a pentagon with a rational point on each edge?
Aug 16, 2023 at 23:31 comment added Gerry Myerson Related: math.stackexchange.com/questions/4509194/…
Aug 16, 2023 at 23:10 history edited M. Winter CC BY-SA 4.0
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Aug 16, 2023 at 14:36 comment added Ilya Bogdanov @KentaSuzuki No, you cannot find a regular pentagon in the integer lattice (in any dimension).
Aug 16, 2023 at 14:32 comment added Kenta Suzuki Can all of the vertices of an icosahedron be rational?
Aug 16, 2023 at 10:58 comment added Ilya Bogdanov @GeraldEdgar Thanks! Fixed.
Aug 16, 2023 at 10:56 history edited Ilya Bogdanov CC BY-SA 4.0
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Aug 16, 2023 at 10:48 comment added Gerald Edgar Two different (mis)spellings of icosahedron in one question! Nice question anyway.
Aug 16, 2023 at 10:28 history edited Ilya Bogdanov
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Aug 16, 2023 at 10:23 history asked Ilya Bogdanov CC BY-SA 4.0