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Aug 16, 2023 at 15:32 comment added Pritam Majumder @IlyaBogdanov Ah! I see, Thanks. I think that works. So basically, we start with a node $v$, then fold the edges incident to $v$ to a single edge $vv_1$, then fold the rest of the edges incident to $v_1$ to an edge $v_1v_2$, and so on. And this works for any bipartite graph with equal edge lengths (need not be skeleton graph of a polytope)
Aug 16, 2023 at 9:21 comment added Ilya Bogdanov Is it possible to implement a physical argument? Let the skeleton (where vertices are hinges) hand on one fixed vertex $u$. The bipartite structure allows all verticves to fit into a single line (each vertex's distanve to $u$ is just the graph distance), and this clearly priviides the minimum of the pitential energy. The only question is --- if you really hang the skeleton, would it indeed move to that state? (Surely, it iseasy to pass from this state to a one-edge.)
Aug 16, 2023 at 9:17 comment added Ilya Bogdanov If you colour the vertices in black and white, each edge has vertices of differ4nt colours. So, fixing one edge, all others should be put there in a unique manner.
Aug 16, 2023 at 9:09 comment added Pritam Majumder @IlyaBogdanov Yes continuous folding (the usual physical folding, i.e. the edges can not cross during folding). Could you please elaborate why it is obvious?
Aug 16, 2023 at 8:26 comment added Ilya Bogdanov Are you asking about continuous folding? The final state for any bipartite skeleton is obvious…
Aug 15, 2023 at 8:38 history edited Pritam Majumder CC BY-SA 4.0
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Aug 15, 2023 at 8:04 history asked Pritam Majumder CC BY-SA 4.0