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Aug 20, 2023 at 20:47 history closed LSpice
Max Horn
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Friedrich Knop
Needs more focus
Aug 12, 2023 at 22:32 answer added Thomas Kojar timeline score: 0
Aug 12, 2023 at 22:24 comment added Thomas Kojar @sara ok I will try to answer it. But this is more of a textbook-question for math.stackexchange.com. In the future, try to post them there. MO is more for research questions.
Aug 12, 2023 at 22:06 comment added sara i add it , it existe in the reference that you shared with me too (page 12 ,a copy past from the book)
Aug 12, 2023 at 22:01 history edited sara CC BY-SA 4.0
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Aug 12, 2023 at 21:36 comment added Thomas Kojar Did you find this statement somewhere? Add the page reference in your above post if you did so that we can go read the original context
Aug 12, 2023 at 21:35 comment added Thomas Kojar What do you mean by the set inside the measure? Did you mean to write $x+B[0,t+2]-Y$?
Aug 12, 2023 at 21:34 comment added Thomas Kojar To be clear the area of planar Brownian motion is zero.
Aug 12, 2023 at 21:29 history edited sara CC BY-SA 4.0
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Aug 12, 2023 at 21:20 history edited sara CC BY-SA 4.0
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Aug 12, 2023 at 20:38 comment added sara ok , i'll do that
Aug 12, 2023 at 20:33 comment added Thomas Kojar @sara you can edit your above post and add those details so that a person can answer it below. Specify what R is. and what you mean by x... do you mean any set A that contains x?
Aug 12, 2023 at 20:31 comment added sara @ThomasKojar Thank you so much
Aug 12, 2023 at 20:27 comment added sara @LSpice i mean for every $x \in \mathbb{R}^2$ it give the Lebesgue measure of [a set involving $x$]
Aug 12, 2023 at 20:21 comment added LSpice Re, what does "take $x$ to be the Lebesgue measure of [a set involving $x$]" mean?
Aug 12, 2023 at 20:14 comment added Thomas Kojar @sara ok I edit that in your question above.
Aug 12, 2023 at 20:00 comment added sara Let $B$ be a standart brownian motion , and $R$ a function defined on $\mathbb{R}^2$ and take $x$ to the Lebesgue measure of $B[0,1]\cap (x+B(t+2)-B(2)+B(1))$ \\ $Y=B(2)-B(1)$ \\ why $E(R(Y))=1/2pi\int_{\mathbb{R}^2}e^{-|x|^2}E(R(x))dx$
Aug 12, 2023 at 19:21 review Close votes
Aug 20, 2023 at 20:47
Aug 12, 2023 at 19:00 comment added Thomas Kojar did you have any specific questions about it? The "potential theory" and BM chapter in Peres-Morters goes into detail. There are many notes on this topic math.uchicago.edu/~may/VIGRE/VIGRE2011/REUPapers/Hansen.pdf
Aug 12, 2023 at 17:34 history edited YCor CC BY-SA 4.0
formatting
S Aug 12, 2023 at 17:12 review First questions
Aug 12, 2023 at 23:00
S Aug 12, 2023 at 17:12 history asked sara CC BY-SA 4.0