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Aug 12, 2023 at 14:38 comment added Ville Salo Yeah, this agrees with my intuition. But I haven't done an argument of this type in the one-sided setting, so I'm not sure on the details of consistently picking which part is repeated.
Aug 12, 2023 at 14:19 comment added Sam van G Looking at the proof of your Theorem 1, I think that, in the setting of our given graph $G$, "suitably repeatable part" could mean the following: for any finite word $w \in 2^*$, write $H(w)$ for the relation on vertices of $G$ defined by $u H(w) v$ iff there is a path in $G$ from $u$ to $v$ labeled by $w$. Then a finite factor $w$ of $y \in 2^\omega$ is suitable if $H(w)$ is an idempotent relation. Does that fit with your intuitions?
Aug 12, 2023 at 7:14 comment added Sam van G For the remainder of your comments, we will need a while to think about it and read your work. It would be great if these methods can help solve it.
Aug 12, 2023 at 7:12 comment added Sam van G Thanks for this! First, you’re right that it was ambiguous, we strictly speaking only need to decide whether or not there exists a homomorphism, but typically think about deciding the existence of surjections (which clearly suffices - not completely sure about the other direction though so I edited the question to be less ambiguous).
Aug 12, 2023 at 5:12 history answered Ville Salo CC BY-SA 4.0