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Aug 12, 2023 at 17:16 comment added Thomas Kojar I didn't say it is necessary, just sufficient based on the linked article in order to get a convex function.
Aug 12, 2023 at 17:09 comment added Panopticon I don't think that A need be negative definite for convergence to zero-- this is manifestly not required in the one dimensional case (geometric brownian motion), where the correct condition is A-B^2/2 < 0.
Aug 11, 2023 at 23:12 history edited Thomas Kojar CC BY-SA 4.0
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Aug 11, 2023 at 22:55 history edited Thomas Kojar CC BY-SA 4.0
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Aug 11, 2023 at 22:37 history answered Thomas Kojar CC BY-SA 4.0