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Apr 12 at 16:41 answer added Miroslav Olšák timeline score: 2
Nov 9, 2023 at 18:34 vote accept Sam van G
S Aug 14, 2023 at 13:52 history suggested Jules Lamers CC BY-SA 4.0
corrected spelling, see https://en.wikipedia.org/wiki/Dutch_name#Tussenvoegsels
Aug 14, 2023 at 12:40 review Suggested edits
S Aug 14, 2023 at 13:52
Aug 14, 2023 at 9:44 answer added no_hurry timeline score: 4
Aug 12, 2023 at 11:04 comment added Carl-Fredrik Nyberg Brodda @SamvanG No problem. And of course -- welcome to MO, Sam, it's nice to see you here! :)
Aug 12, 2023 at 10:43 comment added Sam van G Thank you very much for this reference, Carl-Fredrik. It does look relevant and related, not sure how to use it yet.
Aug 12, 2023 at 7:41 comment added Carl-Fredrik Nyberg Brodda Only somewhat related, but counting the number of homomorphic images of de Bruijn graphs is a very difficult problem (see §6 of arXiv:2004.08478). Perhaps some useful ideas can be found in there.
Aug 12, 2023 at 7:10 history edited Sam van G CC BY-SA 4.0
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Aug 12, 2023 at 5:12 answer added Ville Salo timeline score: 6
Aug 11, 2023 at 18:50 answer added 1001 timeline score: 8
Aug 11, 2023 at 17:08 comment added Ville Salo My first guess is that this is decidable, with a "first periodic and aperiodic points, then transitions" type argument, similar to the proofs of the factor/embedding theorems (of symbolic dynamics).
Aug 11, 2023 at 15:36 history edited Sam van G CC BY-SA 4.0
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Aug 11, 2023 at 15:06 comment added Sam van G Thanks, you're right, I added "and "no" otherwise" just to be sure...
Aug 11, 2023 at 15:06 history edited Sam van G CC BY-SA 4.0
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Aug 11, 2023 at 15:04 comment added Joel David Hamkins Your "that is" statement of decidability is incorrect, since you only state the positive requirement. This defines semi-decidability, and indeed your problem is semi-decidable, since we can just search for an $n$ and say Yes when (and if) we find one for which there is a homomorphism using that $B_n$. This will fulfill your "that is" statement, and shows that the problem is computably enumerable (semi-decidable). But decidability should also mean that you say No if and only if there is no such homomorphism. That is, you want the decision procedure to terminate with Yes or No in finite time.
S Aug 11, 2023 at 14:45 review First questions
Aug 11, 2023 at 14:52
S Aug 11, 2023 at 14:45 history asked Sam van G CC BY-SA 4.0