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Aug 11, 2023 at 12:53 comment added Partha I see, noted. Thanks!
Aug 11, 2023 at 12:52 vote accept Partha
Aug 11, 2023 at 12:48 comment added Robert Bryant @Partha: However, the usual convention (which is mine also) is that the volume form on $\mathbb{R}\times M$ is $\mathrm{d}t\wedge\mathrm{vol}(M)$. If you look at Harvey and Lawson's definition of the $\mathrm{Spin}(7)$ form in terms of the $\mathrm{G}_2$ form, you'll see that their convention agrees with this; their $4$-form is $\mathrm{d}t \wedge\sigma + {\ast}_\sigma\sigma$ where $\sigma$ is the $3$-form on $M$.
Aug 11, 2023 at 12:38 comment added Partha I see, shouldn't $\gamma$ be $+*\beta$, for $\alpha_7$ to be self dual? My volume form on $M\times\mathbb{R}$ is vol$(M)\wedge dt$.
Aug 11, 2023 at 1:55 history answered Robert Bryant CC BY-SA 4.0