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Aug 20, 2023 at 19:34 vote accept Asgar
Aug 9, 2023 at 21:32 comment added Carl-Fredrik Nyberg Brodda @JimBelk Very nice! (And, for completeness, elementary arguments show that the depth-$n$ automorphism group is a $2$-group for all $n$).
Aug 9, 2023 at 20:22 comment added Jim Belk @Carl-FredrikNybergBrodda For a very concrete example, there is a natural embedding of the automorphism group $\mathrm{Aut}(T_2)$ of an infinite rooted binary tree into the product of the autuomorphism groups of finite complete rooted binary trees of depth $n$, and nonabelian free subgroups of $\mathrm{Aut}(T_2)$ have been described explicitly as automata groups.
Aug 7, 2023 at 19:37 comment added Dave Benson @Carl-FredrikNybergBrodda Yes, even better...
Aug 7, 2023 at 19:34 comment added Carl-Fredrik Nyberg Brodda Indeed free groups are residually (finite $p$-groups), so there is an infinite product of finite nilpotent groups which is not amenable.
Aug 7, 2023 at 19:11 history answered Dave Benson CC BY-SA 4.0