Timeline for $f(f(x))=\exp(x)-1$ and other functions "just in the middle" between linear and exponential
Current License: CC BY-SA 2.5
4 events
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| Feb 18, 2016 at 14:19 | comment | added | Gottfried Helms | Hmm, the last example $\alpha_2(z)$ needed 128 iterations do get the difference 1 to 5 digits correct for $z=0.5$ and $z=\exp(0.5)-1$ . I'm surprised to read "converges quickly" here. See the Pari/GP-output: $$\small N=128;z1=0.5;z2=d(z1,1); \\ \small a1= 1/3*\log(d(z1,-N))-2/d(z1,-N) + N \\ \small a2= 1/3*\log(d(z2,-N))-2/d(z2,-N) + N \\ \small a1 = -4.24404333184 \\ \small a2 = -3.24404007720 \\ $$ Do I miss something here? | |
| Nov 7, 2010 at 23:06 | history | edited | bo198214 | CC BY-SA 2.5 |
formatting and slight reformulation of the introduction
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| Nov 7, 2010 at 22:46 | history | edited | bo198214 | CC BY-SA 2.5 |
better formlation about petals
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| Nov 7, 2010 at 22:38 | history | answered | bo198214 | CC BY-SA 2.5 |