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Aug 8, 2023 at 17:04 comment added borntomath @GeraldEdgar: do you have a source (perhaps with proof) where I can look up these formulas?
Aug 8, 2023 at 17:01 comment added borntomath Thanks for the comments! It seems to me that the formulas in mathoverflow.net/questions/186303/… don't work for a=1. Since they run from $-\infty$ to $+\infty$ they include n=0 and for a=1 the summand is not defined.
Aug 5, 2023 at 20:42 comment added Gerald Edgar The sum in my reference is $-\infty$ to $\infty$, not $1$ to $\infty$.
Aug 5, 2023 at 15:39 comment added Sidharth Ghoshal @GeraldEdgar i think letting your $q^2$ here mathoverflow.net/questions/186303/… Equal the OP’s $\frac{y}{x}$ recasts their sum with theta functions (assuming your $a=1$ and your $x$ is the reciprocal of OP’s $a$)
Aug 5, 2023 at 13:01 history edited borntomath CC BY-SA 4.0
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Aug 4, 2023 at 10:39 comment added Gerald Edgar Related: math.stackexchange.com/q/4317994/442
Aug 4, 2023 at 10:36 comment added joro Wolfram alpha claims to solve the special case y=1: wolframalpha.com/…
Aug 4, 2023 at 10:01 history asked borntomath CC BY-SA 4.0