Timeline for Does $H^3\times I$ admit a Kähler metric?
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
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Aug 2, 2023 at 20:46 | comment | added | Michael Albanese | Following up on Moishe Kohan's superior explanation, if $M$ is an odd-dimensional stably parallelisable manifold without boundary, then $M\times(0,1)$ admits a complex structure and Kähler metric for the same reason. | |
Aug 2, 2023 at 20:44 | history | edited | Michael Albanese | CC BY-SA 4.0 |
edited title
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Aug 2, 2023 at 1:31 | vote | accept | Chicken feed | ||
Aug 1, 2023 at 17:00 | comment | added | Moishe Kohan | It is parallelizable and every open parallelizable $n$-manifold immerses in $R^n$. | |
Aug 1, 2023 at 14:18 | history | edited | Michael Albanese | CC BY-SA 4.0 |
added 2 characters in body; edited tags
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Aug 1, 2023 at 14:08 | answer | added | Michael Albanese | timeline score: 9 | |
Aug 1, 2023 at 8:13 | history | asked | Chicken feed | CC BY-SA 4.0 |