Skip to main content
7 events
when toggle format what by license comment
Aug 2, 2023 at 20:46 comment added Michael Albanese Following up on Moishe Kohan's superior explanation, if $M$ is an odd-dimensional stably parallelisable manifold without boundary, then $M\times(0,1)$ admits a complex structure and Kähler metric for the same reason.
Aug 2, 2023 at 20:44 history edited Michael Albanese CC BY-SA 4.0
edited title
Aug 2, 2023 at 1:31 vote accept Chicken feed
Aug 1, 2023 at 17:00 comment added Moishe Kohan It is parallelizable and every open parallelizable $n$-manifold immerses in $R^n$.
Aug 1, 2023 at 14:18 history edited Michael Albanese CC BY-SA 4.0
added 2 characters in body; edited tags
Aug 1, 2023 at 14:08 answer added Michael Albanese timeline score: 9
Aug 1, 2023 at 8:13 history asked Chicken feed CC BY-SA 4.0