Timeline for Why Representation of Clifford algebra are constant for an orthonormal frame?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Aug 27, 2023 at 13:48 | comment | added | Ben McKay | Roughly speaking, anything local you do with an orthonormal frame which doesn't involve differentiating can't feel curvature, so looks identical to the same calculation in Euclidean space. | |
| Aug 26, 2023 at 22:08 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 27, 2023 at 21:30 | answer | added | Igor Khavkine | timeline score: 1 | |
| Jul 27, 2023 at 13:54 | comment | added | amilton moreira | @IgorKhavkine where can I find the proof of that? | |
| Jul 27, 2023 at 9:49 | comment | added | Igor Khavkine | I presume that the $ij$ components are with respect to some local trivialization of $W$. If $W$ has no global trivialization, a global version of that equality is a priori impossible. But given a local trivialization, if the Clifford generators are not constant, the trivialization can be adjusted to make them constant. | |
| Jul 26, 2023 at 17:47 | history | asked | amilton moreira | CC BY-SA 4.0 |