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Jul 26, 2023 at 12:41 comment added Ariyan Javanpeykar A bit more explanation: When we say that a field extension $K/\mathbb{Q}_p$ is unramified, we really mean that $\mathbb{Z}_p\subset O_K$ is unramified. But $O_K$ is the normalization (read: integral closure) of $\mathbb{Z}_p$ in $K$.
Jul 26, 2023 at 12:41 comment added Ariyan Javanpeykar @did you're welcome. By definition, by $L/K$ being unramified, I really just meant that the normalization of $B$ in $L$ is unramified. But the normalization $B'\to B$ is a finite surjective morphism and if it is unramified, then it is in fact etale (by normality of $B$). I can highly recommend Liu's book on Arithmetic Geometry.
S Jul 26, 2023 at 12:32 history suggested did CC BY-SA 4.0
small typo correction
Jul 26, 2023 at 11:29 comment added did Thank you @Ariyan! I just wanted to ask why $L/K$ being unramified implies that $B'$ is finite flat etale over $B$ and do you have a good reference for these notions?
Jul 26, 2023 at 11:27 vote accept did
Jul 26, 2023 at 11:27 review Suggested edits
S Jul 26, 2023 at 12:32
Jul 26, 2023 at 7:20 history answered Ariyan Javanpeykar CC BY-SA 4.0