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Yes, Theorem 1.41 of my book Lipschitz Algebras (second edition). But you must interpret ``$\|\nabla f\|_{L^\infty}$'' to mean $\|\,|\nabla f|\,\|_{L^\infty}$ (sup of the norm of the gradient taken in $\mathbb{R}^n$).
Yes, Theorem 1.41 of my book Lipschitz Algebras. But you must interpret ``$\|\nabla f\|_{L^\infty}$'' to mean $\|\,|\nabla f|\,\|_{L^\infty}$ (sup of the norm of the gradient taken in $\mathbb{R}^n$).
Yes, Theorem 1.41 of my book Lipschitz Algebras (second edition). But you must interpret ``$\|\nabla f\|_{L^\infty}$'' to mean $\|\,|\nabla f|\,\|_{L^\infty}$ (sup of the norm of the gradient taken in $\mathbb{R}^n$).
Yes, Theorem 1.41 of my book Lipschitz Algebras. But you must interpret ``$\|\nabla f\|_{L^\infty}$'' to mean $\|\,|\nabla f|\,\|_{L^\infty}$ (sup of the norm of the gradient taken in $\mathbb{R}^n$).
