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Aug 17 at 19:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Jul 24, 2023 at 16:32 answer added Anonymous timeline score: 0
Jul 22, 2023 at 10:02 comment added Anonymous Maybe ${\mathbb{Q}} \times [0,1]^\omega$?
Jul 22, 2023 at 9:45 comment added D.S. Lipham Right, it looks like if $X$ is connected then so is $\sigma X$, and then it cannot be the same as $\mathbb Q\times X$. I wonder what infinite dimensional spaces for $X$ should be considered instead...
Jul 22, 2023 at 9:31 comment added Anonymous Isn't $\sigma X$ connected for the cases you are asking about?
Jul 21, 2023 at 21:42 history edited D.S. Lipham CC BY-SA 4.0
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Jul 21, 2023 at 18:41 history asked D.S. Lipham CC BY-SA 4.0