Timeline for Embedding of Baumslag-Solitar group into a certain group
Current License: CC BY-SA 2.5
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 19, 2021 at 16:03 | answer | added | Carl-Fredrik Nyberg Brodda | timeline score: 3 | |
| Nov 7, 2010 at 4:10 | vote | accept | Kate Juschenko | ||
| Nov 7, 2010 at 4:10 | vote | accept | Kate Juschenko | ||
| Nov 7, 2010 at 4:10 | |||||
| Nov 7, 2010 at 1:11 | comment | added | Kate Juschenko | @Jon:oh, actually if $BS(1,4)$ embeds, then there is a hope | |
| Nov 7, 2010 at 1:09 | comment | added | Kate Juschenko | @Jon Bannon: it has finite quotients, factor by commutator is non-trivial and finite. | |
| Nov 7, 2010 at 1:08 | answer | added | user6976 | timeline score: 8 | |
| Nov 7, 2010 at 1:07 | comment | added | Kate Juschenko | @Jon: the group is a possible candidate for example of non-sofic group | |
| Nov 7, 2010 at 1:03 | comment | added | Kate Juschenko | @Mark: yes, I really want to have 3 relations. For 4 the answer is "yes". | |
| Nov 7, 2010 at 0:58 | comment | added | user6976 | In the standard Higman group (the one without finite quotients), there are 4 generators. You really want to have only 3? | |
| Nov 7, 2010 at 0:51 | history | edited | Kate Juschenko | CC BY-SA 2.5 |
added 18 characters in body; added 11 characters in body
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| Nov 7, 2010 at 0:49 | comment | added | Kate Juschenko | Please check, I've edited the question | |
| Nov 7, 2010 at 0:48 | history | edited | user6976 | CC BY-SA 2.5 |
added 5 characters in body
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| Nov 7, 2010 at 0:48 | history | edited | Kate Juschenko | CC BY-SA 2.5 |
added 36 characters in body
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| Nov 7, 2010 at 0:48 | comment | added | Qiaochu Yuan | The preview and the actual parser treat html tags differently; I've substituted with \langle and \rangle. | |
| Nov 7, 2010 at 0:47 | history | edited | Qiaochu Yuan | CC BY-SA 2.5 |
added 13 characters in body
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| Nov 7, 2010 at 0:42 | history | asked | Kate Juschenko | CC BY-SA 2.5 |