Timeline for Geodesic distance on $\mathrm{SO}(n)$
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 26, 2023 at 13:27 | comment | added | Math_Newbie | @ABIM Because the injectivity radius on $<\operatorname{SO}(n),g)$ is at-least $\pi/\sqrt{2}$? | |
| Jul 26, 2023 at 13:26 | vote | accept | Math_Newbie | ||
| Jul 21, 2023 at 13:02 | comment | added | ABIM | Let me also add that "small enough" means in a ball of radius $R$ where $\pi/\sqrt{2} \le R\le \pi \sqrt{2 \lfloor n/2\rfloor} $; where $R$ is the injectivity radius on $(SO(n),g)$ and $g$ is the aforementioned bi-invariant metric. | |
| Jul 21, 2023 at 4:07 | history | answered | Ramiro Lafuente | CC BY-SA 4.0 |