Timeline for How to obtain the Lagrangian of the fractional classical mechanics
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 26, 2023 at 15:36 | history | edited | Daniele Tampieri | CC BY-SA 4.0 |
Minor Math Jaxing and added reviews to reference.
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| Aug 26, 2023 at 14:27 | answer | added | Nick | timeline score: 1 | |
| Jul 20, 2023 at 18:17 | comment | added | Michael Engelhardt | Well, now you're changing what you're looking for. Then just go back to the start, verify the relationship holds, that's your proof. | |
| Jul 20, 2023 at 17:36 | comment | added | Dante | I am looking for a mathematical proof. | |
| Jul 20, 2023 at 14:47 | comment | added | Michael Engelhardt | Well, you're essentially solving the differential equation $L=xL' - (L')^{\alpha } $ for the function $L(x)$. So the first thing I would do is try a power ansatz $L=cx^b $ ... I don't think there's more to it than that. | |
| Jul 20, 2023 at 14:33 | comment | added | Dante | Yes, by placing the last relation in the previous three relations, I can confirm the authenticity of the relationship. But I want to compute the last relation from previous three relations. | |
| Jul 20, 2023 at 14:15 | comment | added | Michael Engelhardt | Apart from a missing $-V$, you can just verify this works by inserting the final expression for $L$ into the first three defining relations, no? | |
| Jul 20, 2023 at 12:35 | history | asked | Dante | CC BY-SA 4.0 |