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Jul 19, 2023 at 3:52 vote accept Dominic van der Zypen
Jul 18, 2023 at 19:26 answer added Joel David Hamkins timeline score: 8
Jul 18, 2023 at 19:07 comment added Dominic van der Zypen Thanks for your comment, Joel. I don't know whether the existence of a non-Ramsey function is provable in ZF. Also, I am wondering, whether existence can be shown with something weaker than AC, maybe something Tychonoff-ish?
Jul 18, 2023 at 17:43 comment added Joel David Hamkins In a sense any principle provable in ZFC but not in ZF can be seen as a kind of choice principle. So are you looking merely to know that this is independent of ZF? Or do you want specifically a principle that resembles making choices?
Jul 18, 2023 at 16:27 history edited Dominic van der Zypen CC BY-SA 4.0
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Jul 18, 2023 at 16:08 history asked Dominic van der Zypen CC BY-SA 4.0