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Jul 21, 2023 at 14:13 vote accept Medo
Jul 21, 2023 at 0:12 history edited Medo CC BY-SA 4.0
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Jul 21, 2023 at 0:09 vote accept Medo
Jul 21, 2023 at 1:06
Jul 20, 2023 at 22:35 comment added LSpice Your link to an answer went to a question, so I assumed you meant the sole answer, and edited accordingly. I hope that was correct. \\ @MichaelHardy, thanks for adding \tags in your edit! If you combine those with \labels, then one can \eqref them. I edited accordingly In fact, they are global labels per page, so one can \eqref even in an answer or comment (as to \eqref{1} and \eqref{2}).
Jul 20, 2023 at 22:20 history edited LSpice CC BY-SA 4.0
Link to answer
Jul 20, 2023 at 21:28 answer added Jochen Glueck timeline score: 3
Jul 20, 2023 at 0:52 history edited Medo CC BY-SA 4.0
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Jul 19, 2023 at 10:49 comment added Michael Hardy If you can't type the ö in Schrödinger, it is acceptable to write Schroedinger. If it were Schrodinger, it would be pronounced differently.
Jul 19, 2023 at 10:47 history edited Michael Hardy CC BY-SA 4.0
spelling
Jul 19, 2023 at 0:42 comment added Terry Tao There exists a choice of $t$ such that $|Rf(x)| \geq \frac{1}{2} Sf(x)$ (say) for all $x$: one basically chooses $t(x)$ to nearly maximize $|T f(t,x)|$, conceding a factor of 2 so that we don't have to worry about whether the supremum is attained. [There is a small technicality in ensuring that $t$ can be chosen measurably.] This technique is often referred to as "linearizing a maximal operator". I believe it is discussed in Stein's "Harmonic analysis" in the section on maximal operators, though I do not have it handy at present; maybe others can supply more precise references.
Jul 18, 2023 at 16:22 history edited Michael Hardy CC BY-SA 4.0
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Jul 18, 2023 at 16:00 history edited Medo CC BY-SA 4.0
[Edit removed during grace period]
Jul 18, 2023 at 15:52 history edited Medo CC BY-SA 4.0
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Jul 18, 2023 at 15:14 history asked Medo CC BY-SA 4.0