Skip to main content
5 events
when toggle format what by license comment
Jul 18, 2023 at 1:19 comment added Ben C Amazing! If you write this as an answer I will accept it
Jul 18, 2023 at 0:35 comment added eigenbunny it does not. The pullback by any $C^\infty$ map is still a symplectic fibration, and that's all the argument uses.
Jul 17, 2023 at 23:02 comment added Ben C Doesn't this argument rely on the map $S^2 \to B$ being holomorphic but there may be no holomorphic representative.
Jul 17, 2023 at 22:53 comment added eigenbunny You can use the techniques from this: mathoverflow.net/questions/185171/… and pull back your fibration by any map from $S^2$ to $B$. I believe this shows the connecting map to be trivial whenever $f$ is projective.
Jul 15, 2023 at 17:57 history asked Ben C CC BY-SA 4.0