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Let $X$ be a scheme and G be a group acting on $X$. Suppose the action is not free. Consider the quotient sheaf X/G. Can we directly prove that the sheaf quotient is not an algebraic space?

Let $X$ be a scheme and $G$ be a group acting on $X$. Suppose the action is not free. Consider the quotient sheaf $X/G.$ Can we directly prove that the sheaf quotient is not an algebraic space?

Let $X$ be a scheme and G be a group acting on $X$. Suppose the action is not free. Then we know that the sheaf quotient $X/G$ is an Artin stack. But can we directly prove that the sheaf quotient is not an algebraic space?

Let $X$ be a scheme and G be a group acting on $X$. Suppose the action is not free. Consider the quotient sheaf X/G. Can we directly prove that the sheaf quotient is not an algebraic space?

Let X be a scheme and G be a group acting on X. Suppose the action is not free. Then we know that the sheaf quotient X/G is an Artin stack. But can we directly prove that the sheaf quotient is not an algebraic space?

Let $X$ be a scheme and G be a group acting on $X$. Suppose the action is not free. Then we know that the sheaf quotient $X/G$ is an Artin stack. But can we directly prove that the sheaf quotient is not an algebraic space?