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Aug 3, 2023 at 17:56 comment added Iosif Pinelis @SungjinKim : Yes, you are right.
Aug 3, 2023 at 17:04 comment added Sungjin Kim By the same argument with specifying the constant in $O(1/q^2)$, we may obtain a positive lower bound of $f(2)$.
Jul 16, 2023 at 16:22 comment added ninepointcircle Thanks a lot for the answer! I found this problem on one of the t-shirts that were dustributed in a math competition about 10 years ago. Unfortunately, I don't have an answer to the second part of the problem either.
Jul 14, 2023 at 16:13 comment added Iosif Pinelis @GeraldEdgar : You are quite right. For $x=2$, it seems we have to deal with Diophantine approximation to $\pi$, rather than that to a arbitrary irrational number. This seems to be an open problem.
Jul 14, 2023 at 16:13 history edited Iosif Pinelis CC BY-SA 4.0
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Jul 14, 2023 at 15:43 comment added Gerald Edgar Same argument for $1\le x < 2$. But $x=2$ is on the border, this computation does not answer that case.
Jul 14, 2023 at 15:37 history edited Iosif Pinelis CC BY-SA 4.0
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Jul 14, 2023 at 15:28 history undeleted Iosif Pinelis
Jul 14, 2023 at 15:28 history edited Iosif Pinelis CC BY-SA 4.0
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Jul 14, 2023 at 14:58 history deleted Iosif Pinelis via Vote
Jul 14, 2023 at 14:56 history answered Iosif Pinelis CC BY-SA 4.0