Timeline for Is the matrix multiplication exponent $\omega$ independent from the choice of the base field
Current License: CC BY-SA 4.0
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| Jul 14, 2023 at 12:37 | comment | added | Nathaniel Johnston | I believe that the current answer to this question is "we don't know". There's no obvious reason why $\omega_F$ would have to be field-independent, but for all we know at this point it could be the case that $\omega_F = 2$ for every field. | |
| Jul 14, 2023 at 9:31 | history | asked | Nick Chen | CC BY-SA 4.0 |