Timeline for Partitioning a Rectangle into Congruent Isosceles Triangles
Current License: CC BY-SA 2.5
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 9, 2010 at 2:31 | vote | accept | John Iskra | ||
| Nov 9, 2010 at 2:31 | comment | added | John Iskra | Got it. Thank you! That is a really nice proof. | |
| Nov 8, 2010 at 21:56 | comment | added | Fedor Petrov | Not one-to-one, but if we fix triangle (with sides a and b), then both sides of rectangle are linear combinations of a,b with integer coefficients. So, there are at most countably many of them for fixed a,b. | |
| Nov 8, 2010 at 20:43 | comment | added | John Iskra | You seem to be saying that there is a one-to-one correspondence between classes of similar triangles and classes of rectangles of sides of a given ratio. Perhaps I'm misunderstanding your argument, but if I'm not, I don't see why that has to be true. Can you elaborate a bit? Many thanks! | |
| Nov 7, 2010 at 0:42 | history | edited | Joseph O'Rourke | CC BY-SA 2.5 |
While I am editing, might as well fix articles as well: add 'a.'
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| Nov 7, 2010 at 0:03 | history | edited | Joseph O'Rourke | CC BY-SA 2.5 |
Added article "the."
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| Nov 6, 2010 at 21:03 | comment | added | Joseph O'Rourke | Brilliant! $\mbox{}$ | |
| Nov 6, 2010 at 15:07 | history | answered | Fedor Petrov | CC BY-SA 2.5 |