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Jul 14, 2023 at 13:15 comment added LSpice Re, the descriptive text in A266328 seems to say that both $A$ and $B$ are expandable in Taylor series about $0$ with $A(0) = 1$ and $B(0) = 1$. Since $\log(A(x))$ is Integral B(x), it seems to me that this must mean $\log(A(x)) = \int_0^x B(x)\mathrm dx$.
Jul 14, 2023 at 7:37 comment added Notamathematician @LSpice, thank you for comment and for editing too! I don't know much about integrals, so I took the definition of $A(x)$ from A266328.
Jul 13, 2023 at 20:51 comment added LSpice What does "the constant of integration is $0$" mean? It seems to rely on a distinguished choice of 'best' anti-derivative. \\ I assumed "you can only answer the first question" (whose common reading is "you are not capable of answering the second question") should be "you may answer only the first question" (one common reading of which is "it is OK to answer only the first question"), and edited accordingly.
Jul 13, 2023 at 20:50 history edited LSpice CC BY-SA 4.0
can only answer -> may answer only
Jul 13, 2023 at 15:44 history asked Notamathematician CC BY-SA 4.0