Timeline for Can independent Brownian motions hit zero at the same time?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Jul 12, 2023 at 17:53 | vote | accept | Fawen90 | ||
| Jul 12, 2023 at 14:35 | comment | added | Fawen90 | Fantastic. Many thx | |
| Jul 12, 2023 at 14:00 | comment | added | Julius | @Fawen90 I've added a sentence making reference to the fact that your question is about the first time each Brownian motion hits 0. What I have explained is a stronger result. | |
| Jul 12, 2023 at 13:58 | history | edited | Julius | CC BY-SA 4.0 |
added 248 characters in body
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| Jul 12, 2023 at 13:45 | vote | accept | Fawen90 | ||
| Jul 12, 2023 at 17:53 | |||||
| Jul 12, 2023 at 13:45 | comment | added | Fawen90 | Thanks for the answer. $T$ is a typo and I've edited | |
| Jul 12, 2023 at 13:07 | comment | added | Julius | By the way, you have not defined what $T$ is in your question. | |
| Jul 12, 2023 at 13:06 | history | answered | Julius | CC BY-SA 4.0 |