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Nov 6, 2010 at 23:48 comment added Sándor Kovács @Torsten: an example (I think) with a not-basepoint-free system is below.
Nov 6, 2010 at 23:47 comment added Sándor Kovács @Colin: here is why this is not surprising: The section ring of $\mathcal L$, $R=\oplus_n H^0(X,\mathcal L^n)$ describes $Y={\rm Proj}R$ and not $X$. Your condition simply means that the rational map given by some high power of $\mathcal L$ maps onto a projective space. Exactly as in Torsten's example.
Nov 6, 2010 at 18:54 comment added Sándor Kovács @Torsten: thanks for the clarification. I was sure it had to be something different. :) This is a good question. Maybe you should pose it as a question.
Nov 6, 2010 at 16:08 history edited Torsten Ekedahl CC BY-SA 2.5
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Nov 6, 2010 at 13:58 comment added user2529 your answer is unexpected and surprising! (not to say the least, very helpful). Thanks!
Nov 6, 2010 at 13:50 vote accept CommunityBot
Nov 6, 2010 at 10:44 history answered Torsten Ekedahl CC BY-SA 2.5