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Jul 19, 2023 at 20:37 comment added H.C Manu Oo, that's a clever little argument, thanks for the calrification @JoelDavidHamkins.
Jul 19, 2023 at 20:34 comment added Joel David Hamkins @H.CManu If you refer to Emil's observation, it goes like this: the ultrapower of my bands of odd-length and the ultrapower of the even-sized bands both consist of continuum many $\mathbb{Z}$-chains sequences of my Giant's belt, so they are isomorphic as infinite graphs. But if 3-colorability were expressible for finite graphs, the even-sized factors would all satisfy the assertion, but the odd-sized factor not. So the ultrapower would satisfy it in the even case but not the odd case, contradicting that the two ultrapowers are isomorphic.
Jul 19, 2023 at 20:19 comment added H.C Manu Sorry I know this should be obvious but I am not sure I understand. Given the fact that we are working with finite graphs, but the ultraproduct is made up of infinite graphs, how do we reach the conclusion of the argument?
Jul 8, 2023 at 12:53 comment added Joel David Hamkins Thanks! I have fixed it.
Jul 8, 2023 at 12:51 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 8, 2023 at 11:42 comment added Andreas Blass +1, but a quibble: "ultrapower" should be "ultraproduct".
Jul 8, 2023 at 5:49 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 22:58 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 22:52 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 22:40 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 21:32 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 21:21 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 21:19 comment added Emil Jeřábek Ah, yes, wheels. I couldn’t remember what the official name was.
Jul 7, 2023 at 21:17 comment added Joel David Hamkins I see, bicycle wheels with an odd number of spokes! And that idea will generalize to every finite $n$.
Jul 7, 2023 at 21:15 comment added Emil Jeřábek Btw, a perhaps easier way of going from 2-colourability to 3-colourability is to take the cycles and just add an extra vertex adjacent to all vertices of the cycle. This also generalizes to $k$-colourability for any constant $k\ge2$.
Jul 7, 2023 at 21:12 comment added Joel David Hamkins Yes, I agree. Even when restricting to finite graphs, we cannot express it.
Jul 7, 2023 at 21:07 comment added Emil Jeřábek Since the ultrapower of odd-sized bands and the ultrapower of even-sized bands are the same, this actually shows that no first-order sentence defines 3-colourability on finite graphs.
Jul 7, 2023 at 21:04 history edited Joel David Hamkins CC BY-SA 4.0
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Jul 7, 2023 at 20:58 history answered Joel David Hamkins CC BY-SA 4.0