Timeline for Does a subset with small cardinality represent the whole set?
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
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Jul 9, 2023 at 11:45 | vote | accept | Math_Y | ||
Jul 9, 2023 at 11:44 | comment | added | Math_Y | Yes. $\alpha$-stable distributions. | |
Jul 7, 2023 at 14:42 | comment | added | usul | Does there exist a distribution that satisfies this? | |
Jul 7, 2023 at 4:18 | answer | added | Fedor Petrov | timeline score: 4 | |
Jul 7, 2023 at 3:19 | history | edited | Math_Y | CC BY-SA 4.0 |
added 12 characters in body
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Jul 6, 2023 at 20:32 | comment | added | Michael Hardy | I would have written $F(x)= \Pr(X>x) = x^{-0.5} \text{ for } x\ge 1$ (being explicit about that lower bound). And also "a sample of $N$ independent observations from this distribution" rather than "$N$ samples from this distribution." $\qquad$ | |
Jul 6, 2023 at 18:04 | comment | added | Math_Y | Thank you. You are right, I fixed it. I will be grateful if you write the answer in detail. I would like to know the details of such an analysis. | |
Jul 6, 2023 at 18:02 | history | edited | Math_Y | CC BY-SA 4.0 |
edited body
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Jul 6, 2023 at 10:18 | comment | added | Fedor Petrov | If it should read as $X\geq x$, then we have a large number of order $n^2$ with high probability, thus the terms which are greater than $\sqrt{n} $ dominate the sum, and we have $o(n) $ such numbers | |
Jul 6, 2023 at 10:11 | comment | added | Fedor Petrov | $F(x)=\mathbb{P}[X\leq x]=x^{-0.5}$ is not here a typo? | |
Jul 6, 2023 at 6:41 | history | asked | Math_Y | CC BY-SA 4.0 |