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Jul 2, 2023 at 9:20 answer added tommy1996q timeline score: 0
Jun 30, 2023 at 18:20 comment added tommy1996q Just an idea: a way to look at it is that the operator norm of $A^{-1}$ is equal to the reciprocal of the smallest singular value of $A$. Since the flow changes volumes in a controlled way, the smallest singular value of $A=\nabla _x X$ cannot be "too small", or in the other directions you couldn't stretch enough to have an admissible volume.
Jun 30, 2023 at 16:04 history edited tommy1996q CC BY-SA 4.0
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Jun 30, 2023 at 15:54 history asked tommy1996q CC BY-SA 4.0