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Timeline for Completeness of a normed space

Current License: CC BY-SA 4.0

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Jul 2, 2023 at 12:25 comment added Mathlover Thank you sir for your help.
Jun 30, 2023 at 17:04 comment added Pietro Majer Of course this space can't be complete . Think of $X=\mathbb R$, $g:=e^\theta$ (if you want an example with $\rho<\infty$, or just $g:=1$ to make it simpler). Then $B_g$ is dense in $L^1$, where you can find functions that are everywhere discontinuous and unbounded.
Jun 28, 2023 at 20:33 comment added Mathlover Thank you for your response. Could you please provide more explicit details or clarification?
Jun 28, 2023 at 20:17 comment added Willie Wong I find it hard to believe that $\mathcal{B}_g$ is complete. The inverse of the Cantor function (take a caglad version) can be expressed as the uniform limit of caglad functions , each of which with finitely many discontinuities. Under you hypotheses, uniform convergence implies $\mathcal{B}_g$ convergence, but the inverse Cantor function is not in $\mathcal{B}_g$ as you defined it, as it has infinitely many discontinuity points.
Jun 28, 2023 at 19:45 history asked Mathlover CC BY-SA 4.0