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when toggle format what by license comment
Jun 30, 2023 at 21:15 history edited Simplyorange CC BY-SA 4.0
added 83 characters in body
Jun 28, 2023 at 17:33 comment added Christian Remling The easiest interpretation in this context is as the Fourier multiplier $(1+|\xi|)^{\epsilon}$ (that is, applying the operator to an $f$ is the same as multiplying $\widehat{f}(\xi)$ by the multiplier I gave). Alternatively, you could use functional calculus, at least when $p=2$, since $-\Delta$ is self-adjoint on $L^2(\mathbb R^n)$.
Jun 28, 2023 at 5:34 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing (norm sign and bracket scaling)
Jun 28, 2023 at 3:02 history asked Simplyorange CC BY-SA 4.0