Timeline for Cohomology of $\operatorname{GL}_3(\mathbb{F}_2)$
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jun 28, 2023 at 17:36 | comment | added | Noah B | Thanks @DaveBenson! Not sure why my edited question didn't repost, but for those wondering, I asked about the Steenrod squares of $SL(3,2)$. | |
| Jun 28, 2023 at 16:07 | comment | added | Dave Benson | Probably the easiest way to compute the Steenrod action is to restrict to the Sylow $2$-subgroup, which is dihedral of order $8$. Letting $H^*(G,\mathbb{F}_2)=\mathbb{F}_2[x,y,z]/(xy)$ with $|x|=|y|=3$ and $|z|=2$, the answers are: $Sq^1(z)=x+y$, $Sq^2(z)=z^2$, $Sq^1(x)=Sq^1(y)=0$, $Sq^2(x)=xz$, $Sq^2(y)=yz$. Ah! your question seems to have disappeared while I was typing an answer. | |
| Jun 28, 2023 at 14:46 | comment | added | Noah B | Thank you for the great answer! | |
| Jun 26, 2023 at 22:48 | history | edited | LSpice | CC BY-SA 4.0 |
Link, and name of paper
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| Jun 26, 2023 at 22:16 | history | edited | Dave Benson | CC BY-SA 4.0 |
added 306 characters in body
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| Jun 26, 2023 at 21:46 | history | undeleted | Dave Benson | ||
| Jun 26, 2023 at 20:54 | history | deleted | Dave Benson | via Vote | |
| Jun 26, 2023 at 20:30 | history | edited | Dave Benson | CC BY-SA 4.0 |
added 140 characters in body
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| Jun 26, 2023 at 20:23 | history | answered | Dave Benson | CC BY-SA 4.0 |